Question: Q. 2. Calculate the energy in fusion reaction: ${ }{1} \mathrm{H}^{2}+{ }{1} \mathrm{H}^{2} \rightarrow{ }{2}^{3} \mathrm{He}+{ }{0} n^{1}
A [Delhi Set I, II, III 2016]
Solution:
Ans. Total Binding energy of Initial System
$$ \text { i.e., } \quad{ }{1} \mathrm{H}^{2}+{ }{1} \mathrm{H}^{2}=(2.23+2.23) \mathrm{MeV} $$
Binding energy of final system i.e.,
Hence energy released
[CBSE Marking Scheme 2016]
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