SATHEE: moving-charges-and-magnetism Question 9

Moving Charges And Magnetism

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moving-charges-and-magnetism Question 9

Question: Q. 1. (i) State Biot-Savart’s law in vector form expressing the magnetic field due to an element $\vec{d l}$ carrying current $I$ at a distance $r$ from the element.

(ii) Write the expression for the magnitude of the magnetic field at the centre of a circular loop of radius $r$ carrying a steady current $I$ . Draw the field lines due to the current loop.

U] [O.D. Comptt. I, II, III 2014]

Show Answer

Solution:

Ans. (i) According to Biot-Savart’s law, the magnetic field due to a current element $\vec{d l}$ carrying current $I$ at a point $P$ with position vector $\vec{r}$ is given by

$d \vec{B} = \frac{μ_{0}}{4 π} I (\frac{\vec{d l} \times \vec{r}}{r^{3}})$

(ii)

$B = \frac{μ_{0} I}{2 r}$

Field lines :

Moving Charges And Magnetism

moving-charges-and-magnetism Question 9

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Moving Charges And Magnetism

moving-charges-and-magnetism Question 9

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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