SATHEE: moving-charges-and-magnetism Question 4

Moving Charges And Magnetism

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moving-charges-and-magnetism Question 4

Question: Q. 4. A circular current loop of magnetic moment $M$ is in an arbitrary orientation in an external magnetic field $B$ . The work done to rotate the loop by $30^{\circ}$ about an axis perpendicular to its plane is (a) $M B$ . (b) $\frac{\sqrt{3} M B}{2}$ . (c) $\frac{M B}{2}$ . (d) zero.

[NCERT Exemplar]

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Solution:

Ans. Correct option : (d)

Explanation : The work done to rotate the loop in magnetic field $W = M B (\cos θ_{1} - \cos θ_{2})$ .

When current carrying coil is rotated then there will be no change in angle between magnetic moment and magnetic field.

Here, $θ_{1} = θ_{2} = α$

$\Rightarrow W = M B (\cos α - \cos α) = 0$ .

Moving Charges And Magnetism

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Moving Charges And Magnetism

moving-charges-and-magnetism Question 4

?Very Short Answer Type Questions

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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