moving-charges-and-magnetism Question 37

Question: Q. 15. The magnitude F of the force between two straight parallel current carrying conductors kept at a distance d apart in air is given by

F=μ02πI1I2d

where, I1 and I2 are the currents flowing through the two wires

Use this expression, and the sign convention that the :

“Force of attraction is assigned a negative sign and force of repulsion assigned a positive sign”.

Draw graphs showing dependence of F on :

(i) I1I2 when d kept constant

(ii) when the product I1I2 is maintained at a constant positive value.

(iii) when the product I1I2 is maintained at a constant negative value.

Show Answer

Solution:

Ans. We know that F is an attractive (- ve) force when the currents I1 and I2 are ’like’ currents, i.e., when the product I1I2 is positive or when they are flowing in same direction.

Similarly F is a repulsive (+ve) force when the currents I1 and I2 are ‘unlike’ currents, i.e., when the product I1I2 is negative or when they are flowing opposite direction.

Now F(I1I2), when d is kept constant and F1d when I1I2 is kept constant.

The required graphs, therefore, have the forms shown below.

(i)

(ii)

(iii)

2 Long Answer Type Questions



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