SATHEE: moving-charges-and-magnetism Question 3

moving-charges-and-magnetism Question 3

Question: Q. 3. A current carrying circular loop of radius $R$ is placed in the $x - y$ plane with centre at the origin. Half of the loop with $x > 0$ is now bent so that it now lies in the $y - z$ plane. (a) The magnitude of magnetic moment now diminishes.

(b) The magnetic moment does not change.

(d) The magnitude of $B$ at $(0, 0, z), z » R$ is unchanged.

[NCERT Exemplar]

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Solution:

Ans. Correct option : (a)

Explanation: For a circular loop of radius $R$ , carrying current $I$ in $x - y$ plane, the magnetic moment

$M = I \times π R_{2}$

It acts perpendicular to the loop along $z$ -direction.

When half of the eurrent loop is bent in $y - z$ plane, then magnetic moment due to half current loop is $x - y$ plane, $M_{1} \in I (x R_{2} / 2)$ acting along $z$ -direction.

Magnetic moment due to half current loop in $y - z$ plane, $\mathrm{M}{2} \Rightarrow I\left(\pi R{2} / 2\right) $a l o n g$ x$-direction.

Net-magnetic moment due to entire bent current loop

$\begin{aligned} M_{n e t} & = \sqrt{M_{1}^{2} + M_{2}^{2}} & = \sqrt{2} \frac{I π R^{2}}{2} & = \frac{M}{\sqrt{2}} \end{aligned}$

Therefore, $M_{net} < M$ or $M$ diminishes.

Moving Charges And Magnetism

moving-charges-and-magnetism Question 3

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Moving Charges And Magnetism

moving-charges-and-magnetism Question 3

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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