moving-charges-and-magnetism Question 29

Question: Q. 1. (i) Write an expression for the force F acting on a particle of mass m and charge q moving with velocity v in a magnetic field B. Under what conditions will it move in (a) a circular path and (b) a helical path?

(ii) Show that kinetic energy of the particle moving in magnetic field remains constant.

U] [Delhi III 2017]

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Solution:

Ans. (i) Expression for force acting on charged particle 1

(a) Condition for circular path

(b) Condition for helical path

(ii) Showing Kinetic energy is constant

(i) F=q(v×B)

(a) When velocity of charge particle and magnetic field are perpendicular to each othe

(b) When velocity is neither parallel norperpendicular to the magnetic field.

1/2

(ii) The force, experienced by the charged particle, is perpendicular to the instantaneous velocity v, at all instants. Hence the magnetic force cannot bring any change in the speed of the charged particle. Since speed remains constant, the kinetic energy also stays constant.

[CBSE Marking Scheme 2017]

[II Q. 2. State the Lorentz’s force and express it in vector form. Which pair of vectors are always perpendicular to each other? Derive the expression for the force acting on a current carrying conductor of length L in a uniform magnetic field ’ B ‘.

U [Delhi Comptt. I 2017]

Ans. Lorentz force

Expression in vector form 1/2 Identification of pair of vectors Derivation of expression of force 1/2 Lorentz magnetic force is force experienced by a charged particle of charge ’ q ’ moving in magnetic field B with v

Fm=q(v×B)

1/2

[CBSE Marking Scheme, 2017]



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