moving-charges-and-magnetism Question 21

Question: Q. 16. A circular coil, having 100 turns of wire, of radius (nearly) 20 cm each, lies in the XY plane with its centre at the Origin of co-ordinates. Find the magnetic field at the point (0,0,203 cm) when this coil carries a current of (2π)A.

A [Delhi Comptt. 2016]

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Solution:

Ans. The plane of coil is XY plane and field point is on the Z-axis.

Magnetic field on the axial point

B=μ0IR2N2(R2+z2)3/21 =4π×107×2π×(0.2)2×1002[(0.2)2+(0.23)2]3/21/2 =8×0.04×107×1002×0.04×8×0.21/2 =25μT1/2

[CBSE Marking Scheme 2016]

?Long Answer Type Questions

(5 marks each)

[AI Q. 1. (i) Derive an expression for the magnetic field at point on the axis of a current carrying circular loop.

(ii) A coil of 100 turns (tightly bound) and radius 10 cm, carries a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil.

U] [SQP I 2017] Ans. (i) Derivation : 3 (ii) Numerical : 2 (i) Try yourself, Similar to 3 (b), Short Answer Type II

(ii) Since the coil is tightly bound, we may take each circular element to have the same radius R=10 cm=0.1 m, N=100 Magnitude of magnetic field :

B=μ0NI2R B=4π×107×102×12×101 =2π×104 =6.28×104 T

[CBSE Marking Scheme 2017]



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