moving-charges-and-magnetism Question 17

Question: Q. 10. (i) State the condition under which a charged particle moving with velocity v goes undeflected in a magnetic field B.

(ii) An electron, after being accelerated through a potential difference of 104 V, enters a uniform magnetic field of 0.04 T, perpendicular to its direction of motion. Calculate the radius of curvature of its trajectory. U [Foreign I 2017]

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Solution:

Ans. (i) Condition for charge going undeflected 1

(ii) Formula for radius 1/2

Calculation of radius 112

(i) The force experienced, F=q(v×B)1/2

The charge will go undeflected when v is parallel or antiparallel to B

F=0.

[Alternatively,

If v makes an angle of 0 or 180 with B ]

(ii) The KE of electron



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