moving-charges-and-magnetism Question 16

Question: Q. 9. Consider the motion of a charged particle of mass m and charge q moving with velocity v in a magnetic field B.

(i) If v is perpendicular to B, show that it describes a circular path having angular frequency

ω=qB/m.

(ii) If the velocity v has a component parallel to the magnetic field B, trace the path described by the particle. Justify your answer.

U] [Delhi Comptt. I, II, III 2014]

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Solution:

Ans. (i) Force acting on the charged particle, moving with a velocity v, in a magnetic field B :

F=q(v×B)

As, vB, F=qvB

Since, Fv, it acts as a centripetal force and makes the particle move in a circular path in the plane, perpendicular to the magnetic field.

qvB=mv2r

r=mvqB or vr=qBm

Now

ω=vr

ω=qBm

(ii)

The component of velocity v parallel to magnetic field, will make the particle move along the field.

The perpendicular component of velocity v will cause the particle to move along a circular path in the plane perpendicular to the magnetic field. Hence, the particle will follow a helical path, as shown.

[CBSE Marking Scheme, 2014] 1



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