moving-charges-and-magnetism Question 12
Question: Q. 4. Two identical loops
$$ \begin{aligned} & \text {
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Solution:
Ans. Formula 11/2 } \ & \text { Field due to each coil } \ & \text { Magnitude of resultant field } \ & \text { Direction of resultant field } \ & 1 / 2+1 / 2 \ & \text { Field at the centre of a circular coil }=\frac{\mu_{0} I}{2 R} \ & =12 \pi \times 10^{-6} \text { tesla } \quad 1 / 2 \ & =16 \pi \times 10^{-6} \text { tesla } \quad 1 / 2 \ & =(20 \pi) \mu \mathrm{T} \end{aligned} $$
Let the field make an angle
(Alternatively :
[Note 1 : Award 2 marks if the student directly calculates
[Note 2 : Some students may calculate the field
[CBSE Marking Scheme 2017]
Detailed Answer :
Try yourself, Similar to Q. 3, Short Answer Type I
