magnetism-and-matter Question 5

Question: Q. 4. A coil of ’ N ’ turns and radius ’ R ’ carries a current ’ I ‘. It is unwound and rewound to make a square coil of side ’ a ’ having same number of turns (N). Keeping the current ’ I ’ same, find the ratio of the magnetic moments of the square coil and the circular coil. C [Delhi Comptt. I, II, III 2013]

Show Answer

Solution:

Ans.

A1=πR2 m1=NIA1 A2=a2 m2=NIA2 m1m2=NIA1NIA2 =πR2a2 m1m2=227(Ra)2

[Square coil] [AI Q. 1. A rectangular coil of sides ’ l ’ and ’ b ’ carrying a current I is subjected to a uniform magnetic field B, acting perpendicular to its plane. Obtain the expression for the torque acting on it.

U] [Delhi Comptt. I, II, III 2014]

Ans. Equivalent magnetic moment of the coil,

( n^= unit vector to the plane of the coil)

 Torque =M×B =Ilbn^×B =0

(as n^ and B are parallel or antiparallel to each other)

[CBSE Marking Scheme 2014]



Table of Contents

NCERT Chapter Video Solution

Dual Pane