SATHEE: electrostatic-potential-and-capacitance Question 42

Electrostatic Potential And Capacitance

electrostatic-potential-and-capacitance Question 42

Question: Q. 16. (i) A parallel plate capacitor $(C_{1})$ having charge $Q$ is connected, to an identical uncharged capacitor $C_{2}$ in series. What would be the charge accumulated on the capacitor $C_{2}$ ?

(ii) Three identical capacitors each of capacitance $3 μ F$ are connected in turn in series and in parallel combination to the common source of $V$ volt. Find out the ratio of the energies stored in two configurations.

A [O.D. Set I, II, III 2016]

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Solution:

Ans. (i) Both caprectors would come to common potontial

$V_{commen} = \frac{Total charge}{Net capacitance} = \frac{Q}{c_{1} c_{2}} (c_{1} + c_{2})$

$\Rightarrow$ charge on second capacitor $(q^{'}) = Q (c_{1} + c_{2})$

(ii) Capacitance in series:

$\frac{1}{c_{net}} = - \frac{1}{c_{1}} + \frac{1}{c_{2}} + \frac{1}{c_{3}} \Rightarrow \frac{1}{c_{5}} = - \frac{1}{3} + \frac{1}{3} + \frac{1}{3} - 1 \Rightarrow c_{3} = 4$

Parallel combination

$C_{pet} = c_{1} + c_{2} + c_{3} \Rightarrow c_{p} = 3 + 3 + 30 q \Leftrightarrow c_{p} = 9$ llF

Ratio of energies $= \frac{1}{2} c_{s} v^{2} : \frac{1}{2} c_{p}, 1 : 9$

$∴$ Ratio of energies in cories ma paralied $= 1.9$

[Topper’s Answer 2016]

Electrostatic Potential And Capacitance

electrostatic-potential-and-capacitance Question 42

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Electrostatic Potential And Capacitance

electrostatic-potential-and-capacitance Question 42

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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