electromagnetic-waves Question 22

Question: Q. 14. Considering the case of a parallel plate capacitor being charged, show how one is required to generalize Ampere’s circuital law to include the term due to displacement current.

U [O.D. I, II, III 2014]

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Solution:

Ans. Ampere circuital law,

Bdl=μ0I

between the plates of capacitor,

1/2

Which is impossible, as there is magnetic field.

Modified ampere circuital law,

Bdl=μ0(IC+ID)

where, ID= Displacement current =ε0dϕEdt.



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