SATHEE: electric-charges-and-fields Question 18

Electric Charges And Fields

electric-charges-and-fields Question 18

Question: Q. 8. Two point charges $q_{1}$ and $q_{2}$ are located at points $(a, 0, 0)$ and $(0, b, 0)$ respectively. Find the electric field due to both these charges at the point $(0, 0, c)$ .

A [CBSE SQP 2013]

Show Answer

Solution:

Ans. We have $\vec{E_{net}} = \vec{E_{1}} + \vec{E_{2}}$

$= \frac{1}{4 π ε_{0}} \cdot \frac{q_{1}}{r_{1}^{3}} \vec{r_{1}} + \frac{1}{4 π ε_{0}} \cdot \frac{q_{2}}{r_{2}^{3}} \vec{r_{2}}$

[AI Q. 1. (i) Derive the expression for electric field at a point on the equatorialline of an electric dipole.

(ii) Depict the orientation of the dipole in (i) stable, (ii) unstable equilibrium in a uniform electric field.

A [Delhi I 2017]

Ans. Derivation of expression of electric field on equatorial line of electric dipole Depiction of orientation for stable and unstable equilibrium in electric field $1 / 2 + 1 / 2$

(i) Let the point ’ $P$ ’ be at a distance ’ $r$ ’ from the mid point of the dipole. where, $\vec{r_{1}} = - a \hat{i} + c \hat{k}$

and $\vec{r_{2}} = - b \hat{j} + c \hat{k}$

$\vec{E_{n e t}} = \frac{1}{4 π ε_{0}} [\frac{q_{1} (- a \hat{i} + c \hat{k})}{{(a^{2} + c^{2})}^{3 / 2}} + \frac{q_{2} (- b \hat{j} + c \hat{k})}{{(b^{2} + c^{2})}^{3 / 2}}] 1$

[CBSE Marking Scheme, 2013]

Electric Charges And Fields

electric-charges-and-fields Question 18

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Electric Charges And Fields

electric-charges-and-fields Question 18

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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