SATHEE: electric-charges-and-fields Question 15

Electric Charges And Fields

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electric-charges-and-fields Question 15

Question: Q. 5. An electric dipole of length $4 cm$ , when placed with its axis making an angle of $60^{\circ}$ with a uniform electric field, experiences a torque of $4 \sqrt{3} Nm$ . Calculate the potential energy of the dipole, if it has charge $\pm 8 nC$ .

A [Delhi I, II, III 2014]

Show Answer

Solution:

Ans. Torque

$\begin{aligned} τ & = p E \sin θ 4 \sqrt{3} & = p E \sin 60^{\circ} = p E \frac{\sqrt{3}}{2} 4 \sqrt{3} & = p E \frac{\sqrt{3}}{2} \end{aligned}$

Hence,

Potential energy,

$p E = 8$

$or U = - 8 \times \cos 60^{\circ} = - 4 J$

[CBSE Marking Scheme, 2014]

Electric Charges And Fields

electric-charges-and-fields Question 15

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Electric Charges And Fields

electric-charges-and-fields Question 15

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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