current-electricity Question 53

Question: Q. 5. (i) State the underlying principle of a potentiometer. Why is it necessary to (a) use a long wire, (b) have uniform area of cross-section of the wire and (c) use a driving cell whose emf is taken to be greater than the emf of the primary cells?

(ii) In a potentiometer experiment, if the area of the cross-section of the wire increases uniformly from one end to the other, draw a graph showing how potential gradient would vary as the length of the wire increases from one end.

R U[Comptt. O.D. I, II, III 2014]

ns. (i) Principle of potentiometer :

The potential drop across the length of a steady current carrying wire of uniform cross-section is proportional to the length of the wire.

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(a) We use a long wire to have a lower value of potential gradient (i.e., a lower ’least count’ or greater sensitivity of the potentiometer.) 1/2

(b) The area of cross-section has to be uniform to get a ‘uniform wire’ as per the principle of the potentiometer.

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(c) The emf of the driving cell has to be greater than the emf of the primary cells as otherwise no balance point would be obtained.

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(ii) Potential gradient, k=VL

The required graph is as shown below :

1

[CBSE Marking Scheme 2014]

Q. 6. State the underlying principle of a potentiometer. Write two factors on which the sensitivity of a potentiometer depends.

In the potentiometer circuit shown in the figure, the balance point is at X. State, giving reason, how the balance point is shifted, when :

(i) resistance R is increased ?

(ii) resistance S is increased, keeping R constant ?

U] [Delhi Comptt. I, II, III, 2013]

Show Answer

Solution:

Ans. Try yourself Similar to Q. 5 (a), Short Answer Type Questions-II.

Factors : There are two factors on which sensitivity of potentiometer depends :

(a) length of potentiometer (l)

(b) potential drop (E)

(i) If resistance R is increased, current through the potentiometer wire will decrease, as a result of which, potential gradient of potentiometer wire also decreases. In such case the balance point X will shift towards point B.

(ii) If resistance S increases, keeping resistance R constant, in such case the balance point X will shift towards A.

[CBSE Marking Scheme 2013]



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