current-electricity Question 49

Question: Q. 2. Two cells of emf’s approximately 5 V and 10 V are to be accurately compared using a potentiometer of length 400 cm :

(a) The battery that runs the potentiometer should have voltage of 8 V.

(b) The battery of potentiometer can have a voltage of 15 V and R adjusted so that the potential drop across the wire slightly exceeds 10 V.

(c) The first portion of 50 cm of wire itself should have a potential drop of 10 V.

(d) Potentioneter is usually used for comparing resistances and not voltages.

Show Answer

Solution:

Ans. Correct option : (b)

Explanation: Given that,

emf of primary cells are 5 V and 10 V

The potential drop across potentiometer wire must be slightly more than that larger emf 10 V.

So, the battery should be of 15 V and about 4 V potential is dropped by using rheostat or resistances.

Very Short Answer Type Question

(1 marks)

[AI Q. 1. Why is potentiometer preferred over a voltmeter for determining the emf of a cell?

] [Delhi Comptt., 2016]

Ans. Potentiometer does not draw any (net) current from the cell. Voltmeter draws some current from cell, when connected across it, hence it measures terminal voltage.

[CBSE Marking Scheme, 2016] Detailed Answer :

Potentiometer is preferred over voltmeter because voltmeter needs a current to pass through it so as to measure the potential difference. The potential difference being measured by the voltmeter is given as V=EIR1/2 Hence the voltage V measured is less than emf of a battery E. Potentiometer does not draw any current from the cell and hence will not cause such problem and can measure the emf directly.



Table of Contents

NCERT Chapter Video Solution

Dual Pane