SATHEE: atoms Question 14

atoms Question 14

Question: Q. 5. Calculate the ratio of the frequencies of the radiation emitted due to transition of the electron in a hydrogen atom from its (i) second permitted energy level to the first level and (ii) highest permitted energy level to the second permitted level.

A&E [Comptt. I, II, III 2018]

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Solution:

Ans. Formulae

(i) Frequency of first case

$1 / 2$

(ii) Frequency of second case

Ratio

We have,

(i)

(ii)

$\begin{aligned} h v & = E_{f} - E_{i} & = \frac{E_{0}}{n_{f}^{2}} - \frac{E_{0}}{n_{i}^{2}} h v_{1} & = E_{0} (\frac{1}{1^{2}} - \frac{1}{2^{2}}) = E_{0} \times \frac{3}{4} h v_{2} & = E_{0} (\frac{1}{2^{2}} - \frac{1}{\infty^{2}}) = E_{0} \times \frac{1}{4} \end{aligned}$

$\begin{aligned} = \frac{E_{0}}{n_{f}^{2}} - \frac{E_{0}}{n_{i}^{2}} h v_{1} & = E_{0} (\frac{1}{1^{2}} - \frac{1}{2^{2}}) = E_{0} \times \frac{3}{4} h v_{2} & = E_{0} (\frac{1}{2^{2}} - \frac{1}{\infty^{2}}) = E_{0} \times \frac{1}{4} ∴ \frac{v_{1}}{v_{2}} & = 3 \end{aligned}$

Atoms

atoms Question 14

Ratio

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Atoms

atoms Question 14

Ratio

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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