alternating-currents Question 10

Question: Q. 1. Show that in the free oscillations of an LC circuit, the sum of energies stored in the capacitor and the inductor is constant in time. U[CBSE SQP 2018-19]

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Solution:

Ans. At an instant t, charge q on the capacitor and the current i are given by :

q(t)=q0cosωt i(t)=q0ωsinωt

Energy stored in the capacitor at time t is

UK=12CV2=12q2C=q022Ccos2(ωt)1

Energy stored in the inductor at time t is

UM=12Li2 =12Lq02ω2sin2(ωt) =q022Csin2(ωt)(ω=1/LC)1

Sum of energies

UE+UM=q022C(cos2ωt+sin2ωt)

=q022C

This sum is constant in time as q0 and C, both are time-independent.

[CBSE Marking Scheme 2017]

[AT Q. 2. Obtain the expression for the energy density of magnetic field B produced in the inductor.

U] [Delhi Comptt. 2016]

Ans. Instantaneous Induced emf in an inductor when current changes through it

e=LdIdt

Hence, instantaneous applied voltage

e=V=LdIdt

Work done, dW=V.dq= VIdt

dW= LIdI 

Long Answer Type Questions

dW=0ILIdI W=12LI2

Energy density, U= total energy stored  volume 1/2

U=(12)LI2Al=12(LI)IAl

 Flux =NBA=LI

and

B=μ0NIlI=Blμ0N1/2

=12(NBA)Blμ0NAl=B22μ01/2

[CBSE Marking Scheme 2016]

(5 marks each)



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