SATHEE: alternating-currents Question 1

Alternating Currents

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alternating-currents Question 1

Question: Q. 1. If the $r m s$ current in a $50 Hz AC$ circuit is $5 A$ , the value of the current $1 / 300 s$ after its value becomes zero is (a) $5 \sqrt{2} A$ . (b) $5 \sqrt{\frac{3}{2}} A$ . (c) $\frac{5}{6} A$ . (d) $\frac{5}{\sqrt{2}} A$ .

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Solution:

Ans. Correct option : (b) Explanation :

Here, $I_{rms} = 5 A, v = 50 Hz$ and $L = \frac{1}{300} s$

$I_{0} = Peak value = \sqrt{2} I_{r m s} = \sqrt{2} \times 5 = 5 \sqrt{2} A$

Now, $I = I_{0} \sin ω t = 5 \sqrt{2} \sin 2 π v t$

$= 5 \sqrt{2} \sin 2 π \times 50 \times \frac{1}{300} = 5 \sqrt{\frac{3}{2}} A$

Alternating Currents

alternating-currents Question 1

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Alternating Currents

alternating-currents Question 1

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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