SATHEE: Work Energy And Power Question 95

Work Energy And Power Question 95

Question: A rubber ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing, it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of [CBSE PMT 1998]

Options:

A) 16/25

B) 2/5

C) 3/5

D) 9/25

Show Answer

Answer:

Correct Answer: B

Solution:

If ball falls from height $h_{1}$ and bounces back up to height $h_{2}$

then $e = \sqrt{\frac{h_{2}}{h_{1}}}$

Similarly if the velocity of ball before and after collision are $v_{1}$ and $v_{2}$ respectively then $e = \frac{v_{2}}{v_{1}}$

So $\frac{v_{2}}{v_{1}} = \sqrt{\frac{h_{2}}{h_{1}}} = \sqrt{\frac{1.8}{5}} = \sqrt{\frac{9}{25}} = \frac{3}{5}$

i.e. fractional loss in velocity $= 1 - \frac{v_{2}}{v_{1}} = 1 - \frac{3}{5} = \frac{2}{5}$

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Work Energy And Power Question 95

Question: A rubber ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing, it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of [CBSE PMT 1998]

Options:

Answer:

Solution:

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