Work Energy And Power Question 95

Question: A rubber ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing, it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of [CBSE PMT 1998]

Options:

A) 16/25

B) 2/5

C) 3/5

D) 9/25

Show Answer

Answer:

Correct Answer: B

Solution:

If ball falls from height $ h_1 $ and bounces back up to height $ h_2 $

then $ e=\sqrt{\frac{h_2}{h_1}} $

Similarly if the velocity of ball before and after collision are $ v_1 $ and $ v_2 $ respectively then $ e=\frac{v_2}{v_1} $

So $ \frac{v_2}{v_1}=\sqrt{\frac{h_2}{h_1}}=\sqrt{\frac{1.8}{5}}=\sqrt{\frac{9}{25}}=\frac{3}{5} $

i.e. fractional loss in velocity $ =1-\frac{v_2}{v_1}=1-\frac{3}{5}=\frac{2}{5} $



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