SATHEE: Work Energy And Power Question 84

Work Energy And Power Question 84

Question: A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be [CBSE PMT 1991]

Options:

A) 11.5 m/s

B) 14.0 m/s

C) 7.0 m/s

D) 9.89 m/s

Show Answer

Answer:

Correct Answer: D

Solution:

$P_{x} = m \times v_{x} = 1 \times 21 = 21 k g m / s$

$P_{y} = m \times v_{y} = 1 \times 21 = 21 k g m / s$

Resultant = $\sqrt{P_{x}^{2} + P_{y}^{2}} = 21 \sqrt{2}$ kg m/s

The momentum of heavier fragment should be numerically equal to resultant of ${\vec{P}}_{x}$

and ${\vec{P}}_{y}$ . $3 \times v = \sqrt{P_{x}^{2} + P_{y}^{2}} = 21 \sqrt{2}$

$v = 7 \sqrt{2}$ = 9.89 m/s

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Work Energy And Power Question 84

Question: A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be [CBSE PMT 1991]

Options:

Answer:

Solution:

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