Work Energy And Power Question 82
Question: A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with a velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocity [NCERT 1983; AFMC 1997]
Options:
A) 100 m/s in the horizontal direction
B) 300 m/s in the horizontal direction
C) 300 m/s in a direction making an angle of
D) 200 m/s in a direction making an angle of
Show Answer
Answer:
Correct Answer: B
Solution:
Momentum of ball (mass m) before explosion at the highest point
Let the velocity of third part after explosion is V
After explosion momentum of system =
By comparing momentum of system before and after the explosion
therefore
