Work Energy And Power Question 61

Question: A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is [IIT 1985; MNR 1990; AIEEE 2002; MP PMT 1994, 97, 2000; JIPMER 2000]

Options:

A) $ MgL $

B) $ MgL/3 $

C) $ MgL/9 $

D) $ MgL/18 $

Show Answer

Answer:

Correct Answer: D

Solution:

$ W=\frac{MgL}{2n^{2}}=\frac{MgL}{2{{(3)}^{2}}}=\frac{MgL}{18} $ (n = 3 given)



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