Work Energy And Power Question 324

Question: Two masses connected by a mass less spring .are placed on a horizontal smooth surface. The spring is initially compressed by 3 cm. The system is released from rest. The velocity (in m/s) of the 2 kg mass, when spring attains natural length is to

Options:

A) $ \sqrt{\frac{3}{2}} $

B) $ \sqrt{\frac{2}{3}} $

C) $ \frac{3}{2} $

D) $ \sqrt{3}B=( 1/5x30 ) $

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Answer:

Correct Answer: A

Solution:

[a] $ m_1v_1=m_2v_2 $

and $ \frac{1}{2}Kx_0^{2}=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}. $

Solving $ :v_2=\sqrt{\frac{3}{2}} $



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