Work Energy And Power Question 324
Question: Two masses connected by a mass less spring .are placed on a horizontal smooth surface. The spring is initially compressed by 3 cm. The system is released from rest. The velocity (in m/s) of the 2 kg mass, when spring attains natural length is to
Options:
A) $ \sqrt{\frac{3}{2}} $
B) $ \sqrt{\frac{2}{3}} $
C) $ \frac{3}{2} $
D) $ \sqrt{3}B=( 1/5x30 ) $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ m_1v_1=m_2v_2 $
and $ \frac{1}{2}Kx_0^{2}=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}. $
Solving $ :v_2=\sqrt{\frac{3}{2}} $