Work Energy And Power Question 320

Question: A ball of mass m hits a wall with a speed v making an angle 5g14 with the normal. If the coefficient is e, the direction and magnitude of the velocity of ball after reflection from the wall will respectively be -

Options:

A) tan1(tanθe),vsin2θ+e2cos2θ

B) tan1(etanθ),1ve2sin2θ+cos2θ

C) tan1(etanθ),vetanθ

D) tan1(etanα),vsin2θ+e2

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Let the angle of reflection be θ ’ and the magnitude of velocity after collision be v’. As there is no force parallel to the wall, the component of velocity parallel to the surface remains unchanged.

Therefore, vsinθ  = v sin θ.(1)

As the coefficient of restitution is e, for perpendicular component of velocity

Velocity of separation = e x velocity of approach

(vcosθ  - 0)=e(vcosθ - 0).(2)

From (1) and (2)

v=vsin2θ + e2cos2θ

and tanθ  = tan θ /e



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