SATHEE: Work Energy And Power Question 317

Work Energy And Power Question 317

Question: Two blocks A and B of masses m and 2m placed on a smooth surface are travelling in opposite directions with velocities of 6 m/s and 4 m/s respectively. A perfectly elastic spring is attached to block A. If after collision, velocity of A is $\frac{2}{3} m / s$ towards right , then velocity of block B would be

Options:

A) $\frac{4}{3} m / s$ towards left

B) $\frac{16}{3} m / s$ towards left

C) $\frac{28}{3} m / s$ m/s towards left

D) 4 m/s towards left

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Collision is elastic. Hence,

$V_{2}^{^{'}} - V_{1}^{^{'}} = V_{1} - V_{2}$

or $V_{2}^{^{'}} - \frac{2}{3} = - 6 - 4$

$P I_{2} = \frac{3}{2} \times 20 = 30 c m$

$V_{2}^{^{'}} = - 10 + \frac{2}{3} = - \frac{28}{3} m / s$

or velocity of B is $P^{2} = P_{1}^{2} + P_{2}^{2} + 2 P_{1} P_{2} \cos θ$ towards left.

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Work Energy And Power Question 317

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