Work Energy And Power Question 305

Question: A simple pendulum with a bob of mass ’m’ oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is ‘g’, then the velocity of the bob as it passes through B is

Options:

A) zero

B) $ 2gH $

C) $ mgH $

D) $ \sqrt{2gH} $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] At B, the velocity is maximum.

Taking vertical downward motion of body from A to B, we have, $ u=0,a=g,s=H $

and $ v=? $

$ v^{2}=u^{2}+2as; $

or $ v^{2}=0+2gH $ or $ v=\sqrt{2gH} $



NCERT Chapter Video Solution

Dual Pane