Work Energy And Power Question 296

Question: A particle fells from a height A on a fixed horizontal plane and rebounds. If e is the coefficient of restitution, the total distance travelled by the particle before it stops rebounding is

Options:

A) h2[1e2][1+e2]

B) h[1e2][1+e2]

C) h2[1+e2][1e2]

D) h[1+e2][1e2]

Show Answer

Answer:

Correct Answer: D

Solution:

[d] The velocity of particle after falling through height h u=2gh …(i)

After first rebounding, the velocity of ball is eu and after attaining maximum height it will come to the ground with same velocity eu.

So, after second rebounding its velocity will be e2u .

Similarly, after third fourth…etc reboundings its velocities will be e2u,e4u ,… etc.

Since, it first rebounds with velocity eu so if it attains height h then from v2=u22gh
0=e2u22gh

Or h1=e2u22g=e22gh2g=e2h [from Eq. (i)] The same height the ball travels while approaching ground.

Now, it rebounds with velocity e2u so if it attains a height h2 then 0=e4u22gh2 or h2=e4h

The similar process will follow for further reboundings

Hence, the total distance travelled by the practice before it stops rebounding.

=h+2hi+2h2+=h+2e2h+2e4h+

=h+2e2h(1+e2+e4+)=h+2e2h(11e2)

=h(1+2e21e2)=(1+e21e2)h



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