Work Energy And Power Question 287

Question: An object of mass 2.0 kg makes an elastic collision with another object of mass M at rest and continues to move in the original direction but with one-fourth of its original speed. What is the value of M?

Options:

A) 0.75kg

B) 1.0kg

C) 1.2kg

D) None of these

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Answer:

Correct Answer: D

Solution:

[d] For the object of mass 2.0 kg.

$ \frac{\Delta k}{k}=\frac{k-k/4}{k}=\frac{3}{4} $

Kinetic energy transferred $ \frac{\Delta k}{k}=\frac{4m_1m_2}{{{( {m_1}+m_2 )}^{2}}} $

Here, $ {m_1} = 2.0 kg, m_2= M $

$ \therefore \frac{3}{4}=\frac{4\times 2M}{{{( 2+M )}^{2}}}\Rightarrow M=\frac{2}{3}kgor6kg $



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