SATHEE: Work Energy And Power Question 285

Work Energy And Power Question 285

Question: A ball of mass m moving with a constant velocity strikes against a ball of same mass at rest. If e= coefficient of restitution, then what will be the ratio of velocity of two balls after collision?

Options:

A) $\frac{1 - e}{1 + e}$

B) $\frac{e - 1}{e + 1}$

C) $\frac{1 + e}{1 - e}$

D) $\frac{2 + e}{e - 1}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] As $u_{2} = 0 a n d m_{1} = m_{2}$

therefore from $m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$ We get $u_{1} = v_{1} + v_{2}$

Also, $e = \frac{v_{2} - v_{1}}{u_{1}} = \frac{v_{2} - v_{1}}{v_{2} + v_{1}} = \frac{1 - v_{1} / v_{2}}{1 + v_{1} / v_{2}}$ which gives $\frac{v_{1}}{v_{2}} = \frac{1 - e}{1 + e}$

Work Energy And Power Question 285

Question: A ball of mass m moving with a constant velocity strikes against a ball of same mass at rest. If e= coefficient of restitution, then what will be the ratio of velocity of two balls after collision?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Work Energy And Power Question 285

Question: A ball of mass m moving with a constant velocity strikes against a ball of same mass at rest. If e= coefficient of restitution, then what will be the ratio of velocity of two balls after collision?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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