Work Energy And Power Question 269

Question: A force applied by an engine of a train of mass $ 2.05\times 10^{6} kg $ changes its velocity from 5m/s to 25 m/s in 5 minutes. The power of the engine is

Options:

A) 1.025 MW

B) 2.05 MW

C) 5 MW

D) 6 MW

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ Power=\frac{Work done}{Time}=\frac{\frac{1}{2}m( v^{2}-u^{2} )}{t} $

$ P=\frac{1}{2}\times \frac{2.05\times 10^{6}\times [ {{( 25 )}^{2}}-( 5^{2} ) ]}{5\times 60} $

$ P = 2.05\times 10^{6}W= 2.05 MW $



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