SATHEE: Work Energy And Power Question 259

Work Energy And Power Question 259

Question: In figure, a block having a mass of 5 kg is released from rest, where the spring acting on the body are horizontal and have a tension of 50 N. The force constant of each spring is, $k = 500 N / m$ . The velocity of the block after it has descended by 0.3m.

Options:

A) 0

B) I m/s

C) 2 m/s

D) none

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $x_{i} = \frac{50}{500} = 0. l m ℓ_{i} = 0.4 - 0.1 = 0.3 m$

$x_{f} = \sqrt{{0.4}^{2} - {0.3}^{2}} - 0.3 = 0.2 m$

$2 \times \frac{1}{2} k x_{i}^{2} + m g \times 0.3 = 2 \times \frac{1}{2} k x_{f}^{2} + \frac{1}{2} m v^{2} \Rightarrow v = 0$

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Work Energy And Power Question 259

Question: In figure, a block having a mass of 5 kg is released from rest, where the spring acting on the body are horizontal and have a tension of 50 N. The force constant of each spring is, k=500N/m . The velocity of the block after it has descended by 0.3m.

Options:

Answer:

Solution:

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Question: In figure, a block having a mass of 5 kg is released from rest, where the spring acting on the body are horizontal and have a tension of 50 N. The force constant of each spring is, $k = 500 N / m$ . The velocity of the block after it has descended by 0.3m.