Work Energy And Power Question 259

Question: In figure, a block having a mass of 5 kg is released from rest, where the spring acting on the body are horizontal and have a tension of 50 N. The force constant of each spring is, $ k=500N/m $ . The velocity of the block after it has descended by 0.3m.

Options:

A) 0

B) I m/s

C) 2 m/s

D) none

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ x _{i}=\frac{50}{500}=0.lm{\ell _{i}}=0.4-0.1=0.3m $

$ x _{f} =\sqrt{{{0.4}^{2}}- 0.3^{2}} -0.3= 0.2m $

$ 2\times \frac{1}{2}kx_i^{2}+mg\times 0.3=2\times \frac{1}{2}kx^2 _{f}+\frac{1}{2}mv^{2}\Rightarrow v=0 $



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