Work Energy And Power Question 253

Question: Two blocks of masses m1=10kgandm2=20kg are connected by a spring of stiffness k=200N/m . The coefficient of friction between the blocks ’ and the fixed horizontal surface is μ=0.1 . Find the minimum constant horizontal force F (in newtons) to be applied to m, in order to slide the mass my [Takeg=10m/s2]

Options:

A) μm1g+μm2g2

B) μm1g+μm2g

C) μm1g+μm2g2

D) μm1g+μm2g2

Show Answer

Answer:

Correct Answer: A

Solution:

[a] WF+Wsp+WFric=Δk

Fx12kx2μmgx=0andkx=μm2g

F12μm2gμm1g=0F=μm1g+μm2g2



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