Work Energy And Power Question 246

Question: A uniform chain of length 2 m and mass 0.1 kg overhangs a smooth table with its two third part lying on the table. Find the kinetic energy of the chain as it completely slips- off the table.

Options:

A) $ \frac{8}{9}J $

B) $ \frac{12}{5}J $

C) $ \frac{3}{7}J $

D) $ \frac{11}{3}J $

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Answer:

Correct Answer: A

Solution:

[a] $ U_1 =\int\limits_0^{\ell /3}{-\frac{m}{\ell }gxdx=-\frac{1}{18}}mg\ell ; $

$ U_2 =\int\limits_0^{\ell }{-\frac{m}{\ell }gxdx=-\frac{1}{2}}mg\ell ; $

$ loss in P.E. = U_1- U_2 = \frac{4}{9} mg\ell $

$ =\frac{4}{9}\times 0.1\times 10\times 2=\frac{8}{9}J=FinalK.E. $



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