Work Energy And Power Question 238

Question: A ball dropped from a height of 2m reaches to a height of 1.5m before hitting the ground. Then the percentage of potential energy lost is

Options:

A) 25

B) 30

C) 50

D) 100

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ {U_1}=mgh_1andU_2=mgh_2 $

$ % energy lost = \frac{U_1-U_2}{U_1}\times 100 $

$ =\frac{mgh_1-mgh_2}{mgh_1}\times 100=( \frac{h_1-h_2}{h_1} )\times 100 $

$ =\frac{2-1.5}{2}\times 100=25% $



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