SATHEE: Work Energy And Power Question 237

Work Energy And Power Question 237

Question: If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy

Options:

A) 50%

B) 100%

C) 125%

D) 200%

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Initial momentum $(p_{1}) = p,$

Final momentum $(p_{2}) = 1.5$ p and initial kinetic energy $(K_{1}) = K$ .

Kinetic energy $(K) = \frac{p^{2}}{2 m} \propto p^{2}$ Or, $\frac{K_{1}}{K_{2}} = {(\frac{p_{1}}{p_{2}})}^{2} = {(\frac{p}{1.5 p})}^{2} = \frac{1}{2.25}$ or, $K_{2} = 2.25 K .$ Therefore, increase in kinetic energy is 2.25 $K K = 1.25 K o r 125$

Work Energy And Power Question 237

Question: If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy

Options:

Answer:

Solution:

Engineering Preparation

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Important Resources

Other Resources

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Work Energy And Power Question 237

Question: If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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