Work Energy And Power Question 229

Question: 300 J of work is done in sliding a 2 kg block up an inclined plane of height 10m. Taking g=10m/s2 , work done against friction is

Options:

A) 100J

B) zero

C) 1000J

D) 200J

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Work done against gravity =mgsinθ×d

=2×10×10=200J(dsinθ=10)

Actual work done = 300 J Work done against friction =300200=100J



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