Work Energy And Power Question 229

Question: 300 J of work is done in sliding a 2 kg block up an inclined plane of height 10m. Taking $ g=10m/s^{2} $ , work done against friction is

Options:

A) 100J

B) zero

C) 1000J

D) 200J

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Work done against gravity $ =mgsin\theta \times d $

$ =2\times 10\times 10=200J ( dsin\theta =10 ) $

Actual work done = 300 J Work done against friction $ = 300 - 200 = 100 J $



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