Work Energy And Power Question 215

Question: A uniform force of (3i^+k^) newton acts on a article of mass 2 kg. The particle is displaced from position (2i^+k^) meter to position (4i^+3j^k^) meter. The work done by the force on the particle is

Options:

A) 6 J

B) 13 J

C) 15 J

D) 9 J

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Given : F=3i^+j^

r1=(2i^+k^),r2=(4i^+3j^k)

r1=r2r1=(4i^+3j^k)(2i^+k^)

orr=2i^+3j^2k^ So work done by the given force w=f.r

=(3i^+j^).(2i^+3j^2k)=6+3=9J



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