Work Energy And Power Question 212
Question: Two identical beads of $ m=100 $ gram are connected by an inextensible massless string can slide along the two arms AC and BC of a rigid smooth wire frame in a vertical plane. If the system is released from rest, the kinetic energy of the first particle when they have moved by a distance of 0.1 m is $ 8 \times {10^{-3}}J $ . Find the value of $ x.( g=10m/s^{2} )~~~~~~ $
Options:
A) 8
B) 6
C) 9
D) 11
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Let m be the mass of the beads.
By energy conservation $ mgh =\frac{1}{2} mv^2_1+\frac{1}{2}mv^2_2 $ ….(i)
$ \frac{v_1}{v_2}=\frac{4}{3} $ -(ii) $ v_1=\frac{4\sqrt{2}}{5},v_2=\frac{3\sqrt{2}}{5}., $
$ K.E.=\frac{1}{2}\times 100\times {10^{-3}}\times \frac{16\times 2}{25}=64\times {10^{-3}}J $ x=8.
