Work Energy And Power Question 204
Question: A man does a given amount of work in 10 sec. Another man does the same amount of work in 20 sec. The ratio of the output power of first man to the second man is [J&K CET 2005]
Options:
A) 1
B) 1/2
C) 2/1
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ Power=\frac{W}{t}. $ If W is constant then $ P\propto \frac{1}{t} $ i.e. $ \frac{P_1}{P_2}=\frac{t_2}{t_1}=\frac{20}{10}=\frac{2}{1} $
