Work Energy And Power Question 197

Question: A quarter horse power motor runs at a speed of 600 r.p.m. Assuming 40% efficiency the work done by the motor in one rotation will be [Kerala PET 2002]

Options:

A) 7.46 J

B) 7400 J

C) 7.46 ergs

D) 74.6 J

Show Answer

Answer:

Correct Answer: A

Solution:

Motor makes 600 revolution per minute

n = $ 600\frac{revolution}{minute}=10\frac{rev}{\sec } $ .

Time required for one revolution $ =\frac{1}{10} $ sec Energy required for one revolution = power × time = $ \frac{1}{4}\times 746\times \frac{1}{10}=\frac{746}{40}J $

But work done = 40% of input % $ =40\times \frac{746}{40}=\frac{40}{100}\times \frac{746}{40}=7.46J $



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