Work Energy And Power Question 197

Question: A quarter horse power motor runs at a speed of 600 r.p.m. Assuming 40% efficiency the work done by the motor in one rotation will be [Kerala PET 2002]

Options:

A) 7.46 J

B) 7400 J

C) 7.46 ergs

D) 74.6 J

Show Answer

Answer:

Correct Answer: A

Solution:

Motor makes 600 revolution per minute

n = 600revolutionminute=10revsec .

Time required for one revolution =110 sec Energy required for one revolution = power × time = 14×746×110=74640J

But work done = 40% of input % =40×74640=40100×74640=7.46J



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