Work Energy And Power Question 191

Question: A car of mass 1250 kg is moving at 30m/s. Its engine delivers 30 kW while resistive force due to surface is 750N. What max acceleration can be given in the car [RPET 2000]

Options:

A) $ \frac{1}{3}m/s^{2} $

B) $ \frac{1}{4}m/s^{2} $

C) $ \frac{1}{5}m/s^{2} $

D) $ \frac{1}{6}m/s^{2} $

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Answer:

Correct Answer: C

Solution:

Force produced by the engine

$ F=\frac{P}{v}=\frac{30\times 10^{3}}{30} $ =103N

Acceleration= $ \frac{\text{Forward force by engine–resistive force}}{\text{mass of car}} $

$ =\frac{1000-750}{1250}=\frac{250}{1250} $ = $ \frac{1}{5}m/s^{2} $



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