Work Energy And Power Question 172

Question: A body of mass $ m_1 $ is moving with a velocity V. It collides with another stationary body of mass $ m_2. $ They get embedded. At the point of collision, the velocity of the system [DCE 1999, 2001]

Options:

A) Increases

B) Decreases but does not become zero

C) Remains same

D) Become zero

Show Answer

Answer:

Correct Answer: B

Solution:

By momentum conservation before and after collision. $ m_1V+m_2\times 0=(m_1+m_2)v $

therefore $ v=\frac{m_1}{m_1+m_2}V $ i.e. Velocity of system is less than V.



NCERT Chapter Video Solution

Dual Pane