Work Energy And Power Question 161

Question: Two putty balls of equal mass moving with equal velocity in mutually perpendicular directions, stick together after collision. If the balls were initially moving with a velocity of 452ms1 each, the velocity of their combined mass after collision is [Haryana CEE 1996; BVP 2003]

Options:

A) 452ms1

B) 45ms1

C) 90ms1

D) 22.52ms1

Show Answer

Answer:

Correct Answer: B

Solution:

Initial momentum P=m452 i^+m452 j^

therefore |P|=m×90

Final momentum 2m×V

By conservation of momentum 2m×V=m×90 \ V=45m/s



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