Work Energy And Power Question 151

Question: A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in the figure. If it starts its journey from rest at $ x=0 $ , its velocity at $ x=12 $ m is

Options:

A) $ 0m/s $

B) $ 20\sqrt{2}m/s $

C) $ 20\sqrt{3}m/s $

D) $ 40m/s $

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Answer:

Correct Answer: D

Solution:

[d] Area between curve and displacement axis $ =\frac{1}{2}\times (12+4)\times 10=80J $

In this time, body acquires kinetic energy = $ \frac{1}{2}mv^{2} $

By the law of conservation of energy $ \frac{1}{2}mv^{2}=80J $

$ \Rightarrow \frac{1}{2}\times 0.1\times v^{2}=80 $

$ \Rightarrow v^{2}=1600 $

$ \Rightarrow v=40m/s $



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