Work Energy And Power Question 148

Question: The block of mass M moving on a frictionless horizontal surface collides with a spring of spring constant k and compresses it by length L . The maximum momentum of the block after collision is

Options:

A) ML2k

B) zero

C) kL22M

D) MkL

Show Answer

Answer:

Correct Answer: D

Solution:

[d] When block of mass M collides with the spring , its kinetic energy gets converted into elastic potential energy of the spring.

From the law of conservation of energy, 12Mv2=12KL2
v=kML

Where v is the velocity of block by which it collides with spring.

So, its maximum momentum. P=Mv=MkML=MKL

After collision, the block will rebound with same linear momentum.



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