SATHEE: Work Energy And Power Question 140

Work Energy And Power Question 140

Question: A simple pendulum consisting of a mass $M$ attached to a string of length L is released from rest at an angle $a$ . A pin is located at a distance $l$ below the pivot point. When the pendulum swings down, the string hits the pin as shown in the figure. The maximum angle $θ$ which the string makes with the vertical after hitting the pin is

Options:

A) $\cos^{1} [\frac{L \cos a + l}{L + l}]$

B) $\cos^{1} [\frac{L \cos a + l}{L - l}]$

C) $\cos^{1} [\frac{L \cos a - l}{L - l}]$

D) $\cos^{1} [\frac{L \cos a - l}{L + l}]$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Since the pendulum started with no kinetic energy.

Conservation of energy, implies that the potential energy at $Q_{max}$ must be equal to the original potential energy, i.e., the vertical position will be same.

Therefore, $L \cos α = l + (L - 1) c o s θ$

$\Rightarrow \cos θ = \frac{L \cos α - l}{L - 1}$

$\Rightarrow θ = \cos^{- 1} [\frac{L \cos α - l}{L - l}]$

Work Energy And Power Question 140

Options:

Answer:

Solution:

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Work Energy And Power Question 140

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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