Work Energy And Power Question 134
Question: A mass ’m’ moves with a velocity ‘v’ and collides inelastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision [AIEEE 2005]
Options:
A)
B)
C) v
D)
Show Answer
Answer:
Correct Answer: A
Solution:
Let mass A moves with velocity v and collides in elastically with mass B, which is at rest.
According to problem mass A moves in a perpendicular direction and let the mass B moves at angle q with the horizontal with velocity v.
Initial horizontal momentum of system (before collision) = mv ….(i)
Final horizontal momentum of system (after collision)
From the conservation of horizontal linear momentum mv = mV cosq therefore v = V cosq …(iii)
Initial vertical momentum of system (before collision) is zero.
Final vertical momentum of system
From the conservation of vertical linear momentum
therefore
therefore