SATHEE: Work Energy And Power Question 116

Work Energy And Power Question 116

Question: A particle falls from a height h upon a fixed horizontal plane and rebounds. If e is the coefficient of restitution, the total distance travelled before rebounding has stopped is [EAMCET 2001]

Options:

A) $h (\frac{1 + e^{2}}{1 - e^{2}})$

B) $h (\frac{1 - e^{2}}{1 + e^{2}})$

C) $\frac{h}{2} (\frac{1 - e^{2}}{1 + e^{2}})$

D) $\frac{h}{2} (\frac{1 + e^{2}}{1 - e^{2}})$

Show Answer

Answer:

Correct Answer: A

Solution:

Particle falls from height h then formula for height covered by it in nth rebound is given by $h_{n} = h e^{2 n}$

where e = coefficient of restitution,

n = No. of rebound Total distance travelled by particle before rebounding has stopped $H = h + 2 h_{1} + 2 h_{2} + 2 h_{3} + 2 h_{n} + \dots \dots . .$

$= h + 2 h e^{2} + 2 h e^{4} + 2 h e^{6} + 2 h e^{8} + \dots \dots \dots$

$= h + 2 h (e^{2} + e^{4} + e^{6} + e^{8} + \dots \dots .)$

$= h + 2 h [\frac{e^{2}}{1 - e^{2}}] = h [1 + \frac{2 e^{2}}{1 - e^{2}}] = h (\frac{1 + e^{2}}{1 - e^{2}})$

Work Energy And Power Question 116

Question: A particle falls from a height h upon a fixed horizontal plane and rebounds. If e is the coefficient of restitution, the total distance travelled before rebounding has stopped is [EAMCET 2001]

Options:

Answer:

Solution:

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Work Energy And Power Question 116

Question: A particle falls from a height h upon a fixed horizontal plane and rebounds. If e is the coefficient of restitution, the total distance travelled before rebounding has stopped is [EAMCET 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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